By Bill Brohaugh
(Answers to puzzle In May 15 Issue, pg. 1 04.)
Part 2 (the fun part) instructions:
Using the numbers you figured out in Part I, solve
these math problems. To help, I'll give you a hint about the
answer to each problem by giving you a clue to a coin-op
machine that has a name with the answer-number in it.
l.JxE=
2. H - A=
3. B+G=
4. K + H =
5. B -o- A=
6. F+I=
7. FxK=
8. C+D=
9. HxHxB-
10. E - I=
(clue: Midway's 1979 video)
(clue: Bally's 1978 pin based
on a TV show)
(clue: Stern's 1980 pin with
the wizard theme)
(clue: Cent uri's 1981 driving
video)
(clue: Gottlieb's 1981 multi-
ball pin)
(clue: Chicago Coin's 1975
"hit parade" pin)
(clue: same answer as #I)
(clue: Sega 's 1982 game that
would stand in line before
James Bond)
(clue: U.S. Billiards' 1982
video)
(clue: Bally's 1981 update of
a classic pin)
OK . Time for a break . I'll give you two clues that might
help you solve the puzzle, and then we11 jump into some
tougher problems. First clue: A+ G =C. Second clue: D x
D =D.
I I. The square root of A+ the square root of E = _ _ _ _
(clue: Gottlieb's 1932 classic pingame)
12. HJ x (B - K) = _ _ _ _ _ _ (clue: Stern's 1980 pin
designed by Harry Williams)
1·-
13 . The total of A, B, C, D. E, F, G, H. I, J, and K. multi-
plied by G, minus F, divided in half, minus B, divided by
the answer to #I, squared, cubed, plus A, plusH , plus K
(clue: four different pins - Rockola
=
1935, Gottlieb 1937, MC and D 1948 , Williams 1960)
14. (K - F)+(F+ D)+(H - E)+ (1 - K)+(K - C)= _ _ _
(clue: the number in Gottlieb's 1949 pin based on a literary
masterpiece, squared)
15. (A+ G x E -o- A - H 5 +the cosine ofF - I ,478) x (G - G)
=
(clue: this is a trick question)
Pl.A Y METER. June 1. 1983
Solution: Part 2
I. J (2)
x
E (9) = 18 ................ .. (18- Wheeler)
2. H (10) - A (4) = 6 ........ (6-Mi//ion-Do//ar Man)
3. B(8)+G(I)=9 ........................ (9Ball)
4. K (6) + H (10) = 16 .................. (Route 16)
5. B (8) -o- A (4) = 2 ..................... (Force If)
6. F (3) + I (7)
7. F (3)
x
= 10
.............. .... ... (Top Ten)
K (6) = 18 .................. (18- Wheeler)
8. C (5) + D (0) = 5 ............ ... .......... (005)
9. H (10)
x
H (10)
10 . E (9) - I (7)
x
= 2
B (8) = 800 ....... (800 Fathoms)
. ......... .. ......... (Fireba/12)
clues: A (4) + G (I)= C (5)
D (0) X D (0) = D (0)
I I . The square root of A ( 4) is 2; the square root of E (9) is
3. 2 + 3 is 5
(Five Star Final)
12 . H (I 0) to the third power equals I ,000 (I 0 x I 0 x I 0) .
B (8) - K (6) = 2. 1,000 X 2 = 2,000
(Flight 2000)
13 . All the numbers totaled is 55. Multiply that by G (I),
and you still have 55 . Subtract F (3) to get 52. Divide
52 in half to get 26. Subtract B (8) to get 18. Divide by
the answer to# I ( 18) to get I. Square I (I x I) to get I.
Cube I (I x I x I) to get one . Add A (4), add H ( 10), and
K (6) to get the answer: 21 .
14 . K (6) - F (3)
=
3
F (3) + D (0) =
H (I 0) - E (9) =
3
I
I(7) - K(6)=
K (6) C (5) =
I
I
9
(The clue is Gottlieb's Three Muscateers. Three squared is
3 X 3 = 9)
15 . The trick is that G - G = 0 (anything minus itself equals
0). And anything multiplied by 0 is 0, and that's the
answer.
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